tolong aku dongg kak
a
[tex] \sqrt{35} \times \sqrt{20} = \sqrt{7} \times \sqrt{5} \times \sqrt{4} \times \sqrt{5} \\ = 2 \times 5 \times \sqrt{7} \\ = 10 \sqrt{7} [/tex]
b
[tex] \sqrt{128} - \sqrt{72 } = \sqrt{64 \times 2} - \sqrt{36 \times 2} \\ = 8 \sqrt{2} - 6 \sqrt{2} \\ = 2 \sqrt{2} [/tex]
c
[tex] \sqrt{288} = \sqrt{144 \times 2} = 12 \sqrt{2} [/tex]
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